"H_3BO_3 + HF = H[BF_4] + H_2O"
As per reaction ,
"M_2V_2=" Moles of "HF=" Moles of "H_3BO_3=28.6\\times 1.55\\ milimoles=" "44.33\\times 10^{-3} \\ moles"
Weight of "H_3BO_3= Moles\\times Molar \\ mass="
"44.33 \\times 61.83 \\times 10^{-3}=" "2.741 \\ gm"
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