Question

An ice freezer behind a restaurant has a freon leak, releasing 36.23 g of C2H2F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month.

Answer 1

Total number of weeks$=6\times 4=24$

Mass leak rate of freon$=36.23 Kg/week$

Mass leak rate of flourine$= \frac{Flourine \ mass \ in \ Freon}{ M.M.\ Of \ Freon}\times leak\ rate=$ $\frac{19\times 3}{118.5}\times 36.23=17.427\ gm/week$

Total flourine leaked in 6 months$=24\times17.427=418.248\ gm=0.418 Kg$