Answer: 126,750 Pa
Solution:
P1×V1=P2×V2P_1×V_1=P_2×V_2P1×V1=P2×V2
P2=P1×V1V2=101,400 Pa×4 L3.2 L=126,750 PaP_2=\frac{P_1×V_1}{V_2}=\frac{101,400\,Pa×4\,L}{3.2\,L}=126,750\,PaP2=V2P1×V1=3.2L101,400Pa×4L=126,750Pa
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