Question

A beaker contains 220 mL of a 5.48 M HCl(aq) solution. Determine the new concentration of the solution after it is diluted by adding 189 mL of water to the beaker.

Answer 1

Answer: 2.95M

Solution:

$V_1 ×C_1=V_2 × C_2$

$C_2=\frac{V_1×C_1}{V_2}=\frac{220 mL\,×\,5.48 M}{220mL\,+\,189 mL}= 2.95\,M$