Assuming pressure to be constant.
So,V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}T1V1=T2V2 ;
V1=2L;T1=325K;T2=275K;V_1=2L;T_1=325 K;T_2=275 K;V1=2L;T1=325K;T2=275K; Substituting the values,
2325=V2275 ⟹ V2=275×2325=1.69L\frac{2}{325}=\frac{V_2}{275}\implies V_2=\frac{275\times 2}{325}=1.69L3252=275V2⟹V2=325275×2=1.69L
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