Q97088
Solution:
Given:
Initial conditions;
"n_i=2 mol" ---(initial no. of moles)
"P_i=2 atm." ---(initial pressure)
"V_i=5 L" ---(initial volume)
"T_i=300K" ---(initial temperature of gas)
Final conditions;
"n_f=4 mol" ---(final no. of moles)
"P_f=4 atm." ---(final pressure)
"T_f=270K" ---(final temperature)
To find: "V_f" (final volume of the gas)
Using Ideal Gas Law; "PV=nRT"
where, "R=gas constant"
"\\therefore PV\/nT=constant"
"\\implies P_iV_i\/n_iT_i= P_fV_f\/n_fT_f"
"\\therefore V_f=(P_iV_i\/n_iT_i)*(n_fT_f\/P_f)"
Substituting the given values, we get;
"V_f=((2atm*5L)\/(2 mol*300K))" "*(4mol*270K\/4 atm)"
"=4.5L" (Answer)
Thus new volume of the gas is "4.5 L"
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