Here oxygen gas is limiting reagent
So,
From the balanced reaction given
We know that
5 moles of oxygen gas produces 3 moles of "CO_2"
Or
160 gm of "O_2" produces 132 gm of "CO_2"
So,
31.5 gm of "O_2" will produce
"=\\frac{132}{160}\u00d731.5=25.9875\\ gm\\ CO_2"
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