Question

According to the following reaction, how many grams of carbon dioxide will be formed upon the complete reaction of 31.5 grams of oxygen gas with excess propane (C3H8)?

C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g)

Answer 1

Here oxygen gas is limiting reagent

So,

From the balanced reaction given

We know that

5 moles of oxygen gas produces 3 moles of $CO_2$

Or

160 gm of $O_2$ produces 132 gm of $CO_2$

So,

31.5 gm of $O_2$ will produce

$$=\frac{132}{160}×31.5=25.9875\ gm\ CO_2$$