Answer to Question #96377 in General Chemistry for Harpreet

Question

Calculate the mass % of each component in the mixture based on the total mass recovered?( Mass of sand + beaker= 117.8120, mass of salt +1st beaker= 116.7434, mass of salt + 2nd beaker= 117.4350)

Answer 1

Here,

Let the mass of sand be $x$

Mass of 1st beaker be $y$

Mass of 2nd beaker be $z$

Then

Mass of sand + beakers = $x+y+z=117.8120\ \ \ \ .......(1)$

Similarly,

$x+y=116.7434 \ \ \ \ \ .....(2)\\ x+z=117.4350\ \ \ \ \ .........(3)$

Putting the value of (3) in (1)

We get,

$y=0.3770$

Putting the value of y in (2)

We get,

$x=116.3664$

Putting the value of x in (3)

We get ,

$z=1.0686$

Total mass = $117.8120$

Mass percentage of sand

$$=\frac{116.3664×100}{117.8120}=98.773\ ℅$$

Mass percentage of beaker 1 =

$$=\frac{0.3770×100}{117.8120}=0.32\ ℅$$

Mass percentage of beaker 2

$$=\frac{1.0686×100}{117.8120}=0.907\ ℅$$