Here,
Let the mass of sand be x
Mass of 1st beaker be y
Mass of 2nd beaker be z
Then
Mass of sand + beakers = x+y+z=117.8120 .......(1)
Similarly,
x+y=116.7434 .....(2)x+z=117.4350 .........(3)
Putting the value of (3) in (1)
We get,
y=0.3770
Putting the value of y in (2)
We get,
x=116.3664
Putting the value of x in (3)
We get ,
z=1.0686
Total mass = 117.8120
Mass percentage of sand
=117.8120116.3664×100=98.773 ℅ Mass percentage of beaker 1 =
=117.81200.3770×100=0.32 ℅ Mass percentage of beaker 2
=117.81201.0686×100=0.907 ℅
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