Mass of carbon present in 1760.36 g "CO_2"
"=\\frac{12}{44}\u00d71760.36=586.786\\ g"Then,
Moles of carbon = "\\frac{586.786}{12}=48.9"
Mass of nitrogen present in 920.10 g of "NO_2\\\\"
Moles of nitrogen = "\\frac{280}{14}=20"
Mass of oxygen = total mass of caffeine - mass of carbon - mass of nitrogen
"=104.184\\ g"Moles of oxygen = "\\frac{104.184}{16}=6.511"
So,
Ratio of carbon to nitrogen to oxygen
So empirical formula is
"C_{15}N_6O_2"
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