Question

What is the pressure exerted by 8.47 g of krypton with a volume of 1477.2 mL at a temperature of -20.2oC?

Answer 1

Use ideal gas Law

$$PV = nRT$$

As n=m/M, then

$$PV =\frac{m}{M} RT$$

$$P\times1.4772 L =\frac{8.47 g}{83.80\frac{g}{mol}}\times0.082\frac{L\times atm}{K\times mol}\times (-20.2+273.15) K$$

$$P=1.419 atm$$