Answer to Question #96333 in General Chemistry for Angel
What is the pressure exerted by 8.47 g of krypton with a volume of 1477.2 mL at a temperature of -20.2oC?
1
2019-10-11T09:39:29-0400
Use ideal gas Law
"PV = nRT" As n=m/M, then
"PV =\\frac{m}{M} RT"
"P\\times1.4772 L =\\frac{8.47 g}{83.80\\frac{g}{mol}}\\times0.082\\frac{L\\times atm}{K\\times mol}\\times (-20.2+273.15) K"
"P=1.419 atm"
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