Question

The number of grams of NaCl required to prepare 500 mL of 0.100 M NaCl is ________.

Answer 1

Moles of $NaCl$ required$=0.1M\times0.5L=0.05mol$

So, the grams of $NaCl$ required to form given solution$=0.05mol\times58.5\frac{g}{mol}=2.925g$