Solution.
Since we do not specify the name of the acid, then take for a fact that the acid is strong, and the formula for pH is as follows:
pH=−lg[H+]pH = -lg[H^+]pH=−lg[H+]
[H+]=10−pH[H^+] = 10^{-pH}[H+]=10−pH
[H+] = 0.001 M
C=nVC = \frac{n}{V}C=Vn
n=C×Vn = C \times Vn=C×V
n(H+)=0.001×0.056=5.6∗10−5 molen(H^+) = 0.001 \times 0.056 = 5.6*10^{-5} \ molen(H+)=0.001×0.056=5.6∗10−5 mole
Answer:
n(H+)=5.6∗10−5 molen(H^+) = 5.6*10^{-5} \ molen(H+)=5.6∗10−5 mole
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