Question

Determine the number of hydrogen ions in 56cm^3 of solution of pH 3.

Answer 1

Solution.

Since we do not specify the name of the acid, then take for a fact that the acid is strong, and the formula for pH is as follows:

$pH = -lg[H^+]$

$[H^+] = 10^{-pH}$

[H+] = 0.001 M

$C = \frac{n}{V}$

$n = C \times V$

$n(H^+) = 0.001 \times 0.056 = 5.6*10^{-5} \ mole$

Answer:

$n(H^+) = 5.6*10^{-5} \ mole$