Solution.
Since we do not specify the name of the acid, then take for a fact that the acid is strong, and the formula for pH is as follows:
"pH = -lg[H^+]"
"[H^+] = 10^{-pH}"
[H+] = 0.001 M
"C = \\frac{n}{V}"
"n = C \\times V"
"n(H^+) = 0.001 \\times 0.056 = 5.6*10^{-5} \\ mole"
Answer:
"n(H^+) = 5.6*10^{-5} \\ mole"
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