Answer: 326 nm
Solution:
E=hcλE=\frac{hc}{\lambda}E=λhc
λ=hcE\lambda=\frac{hc}Eλ=Ehc
λ=6.626×10−34Js × 3×108m/s6.10×10−19J=3.26×10−6m=326 nm\lambda=\frac{6.626×10^{-34}Js\;×\;3×10^8 m/s}{6.10×10^{-19}J}=3.26×10^{-6}m=326\,nmλ=6.10×10−19J6.626×10−34Js×3×108m/s=3.26×10−6m=326nm
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