Number of moles of maleic acid"=0.168mol =\\frac{19.5g}{M\\frac{g}{mol}}"
So molar mass of maleic acid"=M=\\frac{19.5}{0.168}=116.07\\frac{g}{mol}"
Let atoms of "C" be "x"
Let atoms of "H" be "y"
Let atoms of "O" be "z"
"12\\times x=0.4139\\times116.07"
"1\\times y=0.0347\\times 116.07"
"16\\times z=0.5514\\times116.07"
"x\\approx4"
"y\\approx4"
"z\\approx4"
Hence molecular formula of maleic acid is "C_4H_4O_4"
And the empirical formula is "CHO"
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