Reaction between them is given by-
"2NaOH\\ \\ +H_2SO_4\\ \\to\\ Na_2SO_4\\ \\ +2H_2O"
Molar mass of "H_2SO_4=98\\ g\\ mole^{-1}"
Moles of sulphuric acid taken = "\\frac{5.88}{98}=0.06\\ mole"
Moles of sodium hydroxide taken = "\\frac{6.2}{40}=0.155\\ mole"
here sulphuric acid is limiting agent so
reaction will proceed according to sulphuric acid
"0.06\\ mole\\ H_SO_4\\ will \\ produce\\ same\\ amount\\ of \\ \\ Na_2SO_4\\\\"
Maas of sodium sulphate produced = "moles\\times molar\\ mass=0.06\\times 142=8.52\\ g"
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