Answer to Question #95603 in General Chemistry for haley

Question #95603
Use the following balanced reaction:

Na2​CO3​ + Ca(HC2​H3​O2​)2​ yield 2NaHC2​H3​O2​ + CaCO3​

If you have 5.51 moles of Na2CO3 and 6.01 moles of Ca(HC2H3O2)2, how many moles of NaHC2H3O2 will be produced?
1
Expert's answer
2019-10-02T08:01:22-0400

We've got the balanced equation


"N{a_2}C{O_3} + Ca{(H{C_2}{H_3}{O_2})_2} \\to 2NaH{C_2}{H_3}{O_2} + CaC{O_3}"

and we can see that each 1 mole of "N{a_2}C{O_3}" reacts with 1 mole of "Ca{(H{C_2}{H_3}{O_2})_2}" , so the limited reagent in our situation is "N{a_2}C{O_3}" (because "5.51[{\\text{mol]}} < 6.01[{\\text{mol]}}") . Next, we can see that each 1 mole of "N{a_2}C{O_3}" give us 2 moles of "NaH{C_2}{H_3}{O_2}" , thus in this situation will be produced

"{\\nu _{NaH{C_2}{H_3}{O_2}}}{\\text{ = 2}} \\cdot {\\nu _{N{a_2}C{O_3}}} = 2 \\cdot 5.51[{\\text{mol]}} = 11.02[{\\text{mol]}}"

moles of "NaH{C_2}{H_3}{O_2}" .


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS