Reaction of water with sodium is-
Na(s)+H2O(l)→NaOH(aq)+12H2(g)So, 3 moles of Na will react 3 moles ofWaterNa(s)+H_2O(l)\to NaOH(aq)+\frac{1}{2}H_2(g)\\So,\ 3\ moles\ of \ Na\ will \ react\ 3 \ moles \ of WaterNa(s)+H2O(l)→NaOH(aq)+21H2(g)So, 3 moles of Na will react 3 moles ofWater
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