Question

a muon (a subatomic particle with a mass of 1.884 × 10–25 g) traveling at 335.0 m/s. Answer in nm.

Answer 1

according to De Broglie wavelength

wave length = planck constant / momentum

here mass of muon particle =1.884*10^-28 kg

velocity =335.0 m/s so momentum will be 631.14 *10^-28 kg m s^-1

value of planck constant = 6.62607 * 10 ^-34 m² kg s^-1

thus resulting wavelength 0.01049 * 10^-6 m

= 10.49 nm