As in "Br_2" the oxidation state of "Br" is
And in "BrO_3^{-1}" the oxidation state "Br" of is "+5"
Hence "Br_2" is oxidized to "BrO_3^{-1}" and "NiO_2" is an oxidizing agent
As in "NiO_2" the oxidation state of "Ni" is "+4"
And in "Ni(OH)_2" the oxidation state of "Ni" is "+2"
Hence "NiO_2" is reduced to "Ni(OH)_2" and "Br_2" is a reducing agent
The oxidation half reaction is "Br_2+12OH^{-1}\\to2BrO_3^{-1}+10e^{-1}+6H_2O"
The reduction half reaction is "NiO_2+2H_2O+2e^{-1}\\to Ni(OH)_2+2OH^{-1}"
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Thank you so much! So, element oxidized: bromine formula of oxidizing agent:BrO3^-1 element reduced: nitrogen formula of reduced agent: Ni(OH)2 Is this correct?
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