Answer to Question #95436 in General Chemistry for Brittany Wallace

Question #95436
Br2 + 5NiO2+ 4H2O+ 2OH-2BrO3- + 5Ni(OH)2 In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent? Please include the formula and element of reduced and oxidized.
1
Expert's answer
2019-09-30T04:53:49-0400

As in "Br_2" the oxidation state of "Br" is

And in "BrO_3^{-1}" the oxidation state "Br" of is "+5"

Hence "Br_2" is oxidized to "BrO_3^{-1}" and "NiO_2" is an oxidizing agent

As in "NiO_2" the oxidation state of "Ni" is "+4"

And in "Ni(OH)_2" the oxidation state of "Ni" is "+2"

Hence "NiO_2" is reduced to "Ni(OH)_2" and "Br_2" is a reducing agent

The oxidation half reaction is "Br_2+12OH^{-1}\\to2BrO_3^{-1}+10e^{-1}+6H_2O"

The reduction half reaction is "NiO_2+2H_2O+2e^{-1}\\to Ni(OH)_2+2OH^{-1}"



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Comments

Assignment Expert
01.10.19, 13:12

Dear Brittany Wallace, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.

brittany wallace
30.09.19, 15:58

Thank you so much! So, element oxidized: bromine formula of oxidizing agent:BrO3^-1 element reduced: nitrogen formula of reduced agent: Ni(OH)2 Is this correct?

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