From the definition of normality,
N(H3PO4)=V(H3PO4)ng.eq.(H3PO4)
where ng.eq.(H3PO4) is the number of gram equivalents of solute, and V(H3PO4) is the volume of solution.
ng.eq.(H3PO4)=Meq(H3PO4)m(H3PO4)
where m(H3PO4) - is the mass of phosphoric acid, and Meq(H3PO4) is equivalent mass of acid.
Meq(H3PO4)=n(H+)M(H3PO4)
where M(H3PO4) is molar mass, and n(H+) is the number of replaceable H+ in H3PO4.
Thus, combining these equations we can find the mass of H3PO4:
m(H3PO4)=ng.eq.(H3PO4)⋅Meq(H3PO4)=N(H3PO4)⋅V(H3PO4)⋅n(H+)M(H3PO4)=5Leq⋅0.6L⋅398molg=98g
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