Answer to Question #94416 in General Chemistry for Miracle

Question #94416

How many grams of water are needed to prepare 400 gm of a 0.9% v/v solution of NaCl ?

Expert's answer

W%= m x 100 %/mtotal

m= mtotal x W%. / 100%= 400 x 0.9% / 100 %= 3.6 g.

mwater= 400 - 3.6 = 396.4 g.

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