A liquid in a lab has a density of 1.17 g/cm^3. What is the volume in liters of 3.02 kg of the liquid?
V=mρ=3.02 kg1.17 g/cm3=3.02⋅103 g1.17 gcm3≈2.58⋅103cm3=2.58 L (liters).V = \frac{m}{\rho} = \frac{3.02\text{ kg}}{1.17\text{ g/cm}^3} = \frac{3.02 \cdot 10^3 \text{ g}}{1.17\text{ g}} \text{cm}^3 \approx 2.58 \cdot 10^3 \text{cm}^3 = 2.58\text{ L (liters)}.V=ρm=1.17 g/cm33.02 kg=1.17 g3.02⋅103 gcm3≈2.58⋅103cm3=2.58 L (liters).
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