Answer to Question #89860 in General Chemistry for shen

Question #89860

if 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH = Fe(OH)2(s) + 2NaCl, how many grams of NaCl would be made?

Expert's answer

507 g FeCl2 it is 507/(56+35.5*2) = 3.76mol. Based on the reaction equation of sodium chloride is formed 3,76*2=7,52mol, it is 7.52*(23+35.5) = 440g

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