You need to make an aqueous solution of 0.145 m iron(lI) chloride for an experiment in lab, using a 200 grams of water. How much solid iron(II) chloride should you add?y
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Expert's answer
2019-05-17T03:29:12-0400
Since m(H2O) = 200 g, Vsol ≈ 200 mL = 0.2 L.
n(FeCl2) = C(FeCl2) × V(FeCl2) = 0.145 M × 0.2 L = 0.029 mol.
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