Question #89831
Phenylcarbinol is used in nasal sprays as a preservative. A solution of 0.52 g of the compound in 25.0 g of water has a melting point of-0.36 °C. What is the molar mass of phenylcarbinol? (Kp for water is -1.858°C/m.)
1
Expert's answer
2019-05-22T01:00:07-0400
n=mM=0.52gMn= \frac{m}{M}= \frac{0.52 g}{M}molarity=nm(water)=0.52gM0.025kg=0.52gM×0.025molarity= \frac{n}{m(water)}=\frac{\frac{0.52 g}{M}}{0.025 kg}= \frac{0.52 g}{M\times0.025}

ΔTfp=kf×molarity\Delta T_{fp}=k_f\times molarity

0.36=1.858×0.52M×0.025-0.36= -1.858\times \frac{0.52}{M\times 0.025}

M=107.35gmolM=107.35\frac{g}{mol}


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