Question #89813
40x10^5 grams of Na2CO3= How many particles of Na2CO3
1
Expert's answer
2019-05-17T02:43:12-0400

n(Na2CO3)=40∗105g106g/mol=37735.85molesn(Na2CO3)=\dfrac{40*10^5g}{106g/mol}=37735.85moles

N(Na2CO3)=37735.85moles∗6.02∗1023=2.272∗1028(particles)N(Na2CO3)=37735.85moles*6.02*10^{23}=2.272*10^{28}(particles)




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