Answer to Question #89704 in General Chemistry for Michael

Question

If 8.42 x 10^(24)molecules of ammonium sulphate are allowed to react with excess sodium hydroxide, calculate the volume of ammonia gas produced.

Answer 1

(NH₄)₂SO₄ + 2NaOH = Na₂SO₄ + 2NH₃ + H₂O

n ((NH₄)₂SO₄ = N/N_a

n = 8,42•10²⁴ / 6,02•10²³ = 13.99 mole

n (NH₃) = 27.97 mole

V (NH₃) = n×V_m

V (NH₃) = 27.97 × 22.4 = 626.6 litre