Answer to Question #89688 in General Chemistry for Kaleb

Question #89688
How many grams of KMnO4 are in 3.4L
1
Expert's answer
2019-05-14T03:40:06-0400

"m(solution) =V(solution)*\u03c1(solution)"

"m(KMnO4)=\\dfrac{m(solution)*w(KMnO4,\\%)}{100\\%}"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS