Question #89688
How many grams of KMnO4 are in 3.4L
1
Expert's answer
2019-05-14T03:40:06-0400

m(solution)=V(solution)ρ(solution)m(solution) =V(solution)*ρ(solution)

m(KMnO4)=m(solution)w(KMnO4,%)100%m(KMnO4)=\dfrac{m(solution)*w(KMnO4,\%)}{100\%}


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