Question #89697
A 37.5 M capital L solution contains 0.181 lowercase G a potassiums chromate, K2CrO4. What is the molarity?
1
Expert's answer
2019-05-15T05:47:38-0400

molarity=0.181g∗1000194,19g/mol∗37.5mL=0,0248mol/Lmolarity=\dfrac{0.181g*1000}{194,19g/mol*37.5mL}=0,0248 mol/L


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