An aqueous solution of HCl is added to an aqueous solution of Na(OH) and a reaction occurs. The
concentration of H + ions in the solution is 1.0x10 -5 M, calculate the concentration of the OH –1 ions. Is the
solution more acidic or basic?
pH = -log [H+]
pOH = -log [OH-]
in aqueous solution pH + pOH = 14
Using the above data, we find first the pH, then the pOH and then the OH-concentration.
pH = -log (1*10-5) = 5
pOH = 14 - pH = 14 - 5 = 9
pOH = -log [OH-] = 9
[OH-] = 1 * 10-9 M
If the pH is higher than 7, the solution is alkaline; if it is less than 7, it is acidic; if it is equal to 7, it is neutral.
Answer:
[OH-] = 1 * 10-9
solution is a acidic.
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