Thiocyanic acid (HSCN) has a pKa of 4.0.
In what form would it exist in a solution of pH 0.0?
HSCN => H+ + SCN-
pKa = -log [H+]
4 = -log [H+]
[H+] = 0,0001 mol/l
pH = 0 is a 1mol/l [H+]
therefore, in a solution with pH=0, HSCN is present at 1mol/l
Answer: 1M HSCN
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