Question

A blood sample contains 0.040 g glucose (C₆H₁₂O₆) per 100.0 mL. What is the molarity of glucose in this sample?

Answer 1

M_r - molecular mass of glucose=180g/mol

m - mass of glucose = 0,04 g

V - volume of blood = 100 ml = 0,1 liters

C_M - concentration of molarity = ?

$n = \cfrac {m}{M}= \cfrac {0,04}{180} = 0,0002222 ~mol$

$C_M = \cfrac {n}{V}= \frac {0,002222}{0,1}= 0,002222 ~mol/l$

or 2,222 * 10^-3 mol/l

Answer: 2,222*10^-3 mol/l