Learning Task 3
Determine if liquid water will spontaneously freeze at -10.00 oC? Is it spontaneous at +10.00 oC? What can you say about
the values of ΔSuniv?
ΔSuniv = ΔSsys + ΔSsurr
ΔSsys is positive (22.1 J/K)
T1 = -10.00 C = 263.15 K
T2 = +10.00 C = 283.15 K
ΔSsurr = Q/T < 0!
If Q = 6.00 kJ, then at T1 ΔSuniv < 0 (melting is nonspontaneous, freezing is)
At T2 ΔSuniv > 0 (melting is spontaneous, freezing is not)
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