computethe volume of CO2 produced at 65°C and 2.3 atm when 1.7 g of O2 is used up in the reaction:
C3H8 (s) + 5O2 (g) ——4 H2O(g) + 3H2(g)
"M(O_2)=16 g\/mol"
"n(O_2)=1.7\/16=0.106 mol"
"C_3H_8 +5O_2 \\rightarrow 3CO_2+4H_2O"
"n(CO_2)=0.106x3\/5=0.06 mol"
"PV=nRT"
"V=(nRT)\/P"
T=65+273=338 K
P=208650 Pa
R=8.31 J/(mol K)
"V=0.06x8.31x338\/202650=0.0008 l"
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