Question

computethe volume of CO2 produced at 65°C and 2.3 atm when 1.7 g of O2 is used up in the reaction:

C3H8 (s) + 5O2 (g) ——4 H2O(g) + 3H2(g)

Answer 1

$M(O_2)=16 g/mol$

$n(O_2)=1.7/16=0.106 mol$

$C_3H_8 +5O_2 \rightarrow 3CO_2+4H_2O$

$n(CO_2)=0.106x3/5=0.06 mol$

$PV=nRT$

$V=(nRT)/P$

T=65+273=338 K

P=208650 Pa

R=8.31 J/(mol K)

$V=0.06x8.31x338/202650=0.0008 l$