Answer to Question #328158 in General Chemistry for den

Question

If 37 grams of methanol is produced from the reaction of 60 grams of CO and 6 grams of H2.Determine the reagent,excess reagent, percent yield and theoretical yield of reaction

Answer 1

CO + 2H₂ = CH₃OH

n(H₂)=m(H₂)/Mr(H₂)=6g / 4g/moll = 1.5 moles

n(CO) = m(CO)/Mr(CO) = 60g / 28g/moll = 2.14 moles

CO excess reagent

H₂ limiting reagent

m(CH₃OH) = ( m(H₂)*Mr(CH₃OH) ) / Mr(H₂) = (6g * 32g/moll) / 4g/moll = 48g - theoretical yield

percent yield = (37/48)*100% = 77.1%