Answer to Question #328231 in General Chemistry for rosy cheeks

Question

Calculate the theoretical yield of AlF3 obtained from the reaction of 0.45 mole of Al in the reaction: 2 Al + 3F2= 2 AlF3

Answer 1

2Al + 3F₂ = 2 AlF₃

2 mol Al - 2 mol AlF₃

0.45 mol Al - x mol AlF₃

x = 0.45 mol

m(AlF₃) = n(AlF₃) × Mr(AlF₃) = 0.45 mol × 84 g/mol = 37.8 g

theoretical yield = m_practical / m_theoretical × 100%