A solution prepared by adding 10g of an unknown non-volatile, non-electrolyte solute to 150 g of water. The Boiling point of the solution is elevated by 0.433 0C above the normal boiling point of the solvent. What is the molar mass of the unknown substance?
∆Tf = iKfm
For water, Kf = 1.860 c/kg/mol
i= 1
m= molality of solution.
0.433=1×1.86×(10÷molar mass)×1000÷150
0.433= 124÷molar mass
molar mass=124÷0.433
=286.37
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