5 mL of nitric acid, HNO3, are required to react with 50 mL of a 1.25 M Barium hydroxide, Ba(OH)2 solution:
2 HNO3 (aq) + Ba(OH)2 (aq) --> 2 H2O (aq) + Ba(NO3)2 (aq)
Determine the concentration (Molarity) of the nitric acid solution (HNO3).
1ml=1g
Number of moles of nitric acid;
Molar mass= 63
Moles= 5/63= 0.0794moles
Molarity= moles/ litre
Molarity= 0.0794/1000
= 7.9× 10^-5M
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