Hydrogen peroxide (H2O2) is a powerful oxidizing agent used in concentrated solution in rocket fuels and in diluted solutions is hair bleach. An Aqueous solution of 25% (m/m) has a density of 1.05 g/ml. Calculate the concentration in terms of:
a. Mole Fraction of H2O2
b. Molarity
The molar mass of H2O2 is 34 g mol-1.
The molar mass of H2O is 18 g mol-1.
Assume that 100 g solution is given.
1) Determine the molarity of the solution:
(1.11 g soln / mL soln) × (30 g H2O2 / 100 g soln) × (1 mol H2O2 / 34 g H2O2) × (1000 mL / 1L) = 9.79 M
The molarity of H2O2 solution is 9.79 M
2) Determine the mole fraction of H2O2:
χ(H2O2) = Moles of H2O2 / Total moles of solution
Moles of H2O2 = (30 g H2O2) × (1 mol H2O2 / 34 g H2O2) = 0.88235 mol
Moles of H2O = (70 g H2O) × (1 mol H2O / 18 g H2O) = 3.8889 mol
Total moles of solution = Moles of H2O2 + Moles of H2O = 0.88235 mol + 3.8889 mol = 4.77125 mol
χ(H2O2) = 0.88235 mol / 4.77125 mol = 0.18493 = 0.185
The mole fraction of H2O2 is 0.185
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