Question

A given mass of a gas occupies 150cm cube at 20 degrees Celsius and pressure at 1.013*(10*5) Newton per meter. Calculate the temperature at which the volume is doubled at the same pressure?

Answer 1

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$P_1=P_2$

$\frac{150}{273.15+20}=\frac{2(150)}{T}$

$T=586.3K$