Calculate the molarity and molality of an NH3 solution made up of 35.0 g of NH3 in 75.0 g of water. The density of the solution is 0.982 g/mL
Molarity
"Mass=35+75=110g"
Volume"=110\u00d70.982=108.02ml"
Molar mass of NH"_3=17.031"
Number of moles "=\\frac{35}{17.031}=2.055" moles
Molarity "=" Moles"\/" Litre
"=\\frac{1000}{108.02}\u00d72.055"
"=19.02M"
Molality "=" Moles"\/" kg of solvent
"=2.055\u00d7\\frac{1000}{75}"
"=27.4" mole"\/" "kg"
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