Answer to Question #297896 in General Chemistry for sha

Question #297896

Calculate the molarity and molality of an NH3 solution made up of 35.0 g of NH3 in 75.0 g of water. The density of the solution is 0.982 g/mL


1
Expert's answer
2022-02-16T07:38:02-0500

Molarity


Mass=35+75=110gMass=35+75=110g

Volume=110×0.982=108.02ml=110×0.982=108.02ml

Molar mass of NH3=17.031_3=17.031


Number of moles =3517.031=2.055=\frac{35}{17.031}=2.055 moles



Molarity == Moles// Litre

=1000108.02×2.055=\frac{1000}{108.02}×2.055

=19.02M=19.02M


Molality == Moles// kg of solvent

=2.055×100075=2.055×\frac{1000}{75}

=27.4=27.4 mole// kgkg




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