Question

A reaction produces ∆H = -231 kJ/mol of heat. What is the adiabatic temperature rise of the reaction mixture if the specific heat of the reaction mixture is C_P = 1.9 kJ/(kg·K) and the reactor contains m = 200 kg of the reaction mixture? The density of the reaction mixture is d = 800 kg/m³ and the final concentration of the product is supposed to be C = 2 mol/dm³.

Answer 1

Volume of mixture $\frac{Mass}{Density}=\frac{200}{800}=0.25m^3$

$=250dm^3$

Number of moles$=2×250$

$=500moles$

$\Delta\>H=-231×500$

$=-115500kJ$

$H=mc\Delta\>T$

$\implies115500=200×1.9×\Delta\>T$

$\Delta\>T=304K$