Question

Given the schematic notation: Cu | Cu2+ (0.0200 M) ∥ Ag+

(0.0200 M) | Ag, calculate the cell

potential of this system. Show all calculation.

Answer 1

E cell $=$ E right $-$ E left

Ag⁺ + e^- $\to$Ag_(s) E$\theta=0.799v$

Cu²⁺ +2e^- $\to$ Cu_(s) E$\theta=0.337v$

E$_{Ag^+}/_{Ag}=0.799-0.0592 \>log \>\>\frac{1}{0.0200}=0.6984v$

E $_{Cu^2+}/_{Cu}=0.337-\frac{0.0592}{2}\>log\frac{1}{0.0200}=0.2867v$

E $_{cell}=$ E$_{Ag^+}-$ E$_{Cu^{2+}}=0.6984-0.2867$

$=0.412v$