Question

A 5,5g of a gas contained in 1.50 L at 250C exerts a pressure of 741 torr. What is the molar mass of the gas? (1 atm=760 torr)

Answer 1

PV$=$ nRT

P$=\frac{741}{760}atm=0 .975$

V$=1.5litre$

n$=\frac{5.5}{M}$ Where $M=$ Molar mass

R$=0.0821atm.L/mol.K$

T$=25+273.15=298.15K$

$0.975×\frac{5.5}{M}×0.0821×298.15$

M$=\frac{5.5×0.0821×298.15}{0.975×1.5}$

$=92.05g/mol$