If you have 620.0 g of HNO3 and excess Na2CO3, how many grams of carbon dioxide will be produced?
"2 HNO_3 (aq) + Na_2CO_3 (aq) \u2192 2 NaNO_3 (aq) + CO_2(g)"
Molar mass of "HNO_3" : 63.01 g/mol
"HNO_3=\\frac{620}{63.01}=9.84moles"
Moles "=\\frac{9.85}{2}=4.925moles"
"Mass =44.01\u00d74.925=216.75grams"
Comments
Leave a comment