Question

If you have 620.0 g of HNO₃ and excess Na₂CO₃, how many grams of carbon dioxide will be produced?

Answer 1

$2 HNO_3 (aq) + Na_2CO_3 (aq) → 2 NaNO_3 (aq) + CO_2(g)$

Molar mass of $HNO_3$ : 63.01 g/mol

$HNO_3=\frac{620}{63.01}=9.84moles$

Moles $=\frac{9.85}{2}=4.925moles$

$Mass =44.01×4.925=216.75grams$