1. The fertilizer ammonium sulfate is prepared by the reaction between ammonia and sullfuric acid:
2NH3(g) + H2SO4(aq) -> (NH4)2SO4
a. What is the molar mass of NH3?
b. What is the molar mass of (NH4)2SO4?
c. What is the mole-mole ratio of NH3 to (NH4)2SO4?
d. How many moles of ammonium sulfate is produced when 638.4 g of NH3 reacts completely with H2SO4?
e. How many grams of NH3 is needed to produce 50.0 g of (NH4)2SO4?
a) Molar mass of NH3=17.03g
b)Molar mass of (NH4)2SO4=132.13g
c) Mole-mole ratio=2:1
d)Number of moles =18.74moles
e) 12.88g
Comments
Leave a comment