How many milliliters of water have to be added to 134.1 mL of 0.27 M HCl to reduce the concentration to 0.10 M HCl?
M1V1= M2V2
134.1×0.27= 0.1×X
36.18= 0.1×
x= 361.8
= 361.8-134.1= 227.7ml
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