Answer to Question #255784 in General Chemistry for lilbit

Question #255784

How many milliliters of water have to be added to 134.1 mL of 0.27 M HCl to reduce the concentration to 0.10 M HCl?

Expert's answer

M1V1= M2V2

134.1×0.27= 0.1×X

36.18= 0.1×

x= 361.8

= 361.8-134.1= 227.7ml

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