Answer to Question #243005 in General Chemistry for jio

Question

One hundred kilomoles of wet natural gas containing a mixture of methane (CH4) and ethane (C2H6) are combusted. The mole ratio of total carbon to total hydrogen in fuel is given as 13:50. Assuming complete combustion and 50% excess air entering the combustion chamber, compute for the following:

Answer 1

Molar mass of C₂H₆ = 30.07g/mol

Molar mass of CH4 = 16.04

46.11 × 13/63 = 9.5g

46.11×50/63 =36.6g