Question

Write the balanced overall equation for the followingprocess (equation 3) and calculate

∆HoveralI.

(1) N2 (g) + O2(g) → 2NO(g) ∆H = 180.6 kJ

(2) 2NO(g) + O2(g) → 2NO2(g) ∆H = - 114.2 kJ

(3) ∆Hoverall=?

Answer 1

Reaction

$N_2 (g) + O_2(g) → 2NO(g)$

$NO_2 (g) \to NO(g) +\frac{1}{2}O_2(g)$

$N_2O (g) \to N_2(g)+ \frac{1}{2}O_2(g)$

$N_2O (g) + NO_2(g) → 3NO(g)$

$∆H=∆H_1+(-\frac{1}{2}∆H_2)+\frac{1}{2}∆H_3$

$∆H=180.6+(-\frac{1}{2}-114.2)+\frac{1}{2}(-163.2)$

$∆H=156.1kJ$