This coal gas can be used a fuel: CO(g) + H2(g) + O2(g) → CO2(g) + H2O(g) ∆Ho= ?
2 × (3): 2C(s)+2H2O(g)→2CO(g)+2H2(g)
;
mΔH=262.6 kJ
(2): CO(g)+H2O(g)→CO2(g)+H2(g)
;
mΔH=-41.2 kJ
-(1): CO(g)+3H2(g)→CH4(g)+H2O(g)
;
mΔH=-206.1 J
(4): 2C(s)+2H2O(g)→CH4(g)+CO2(g)
;
mΔH=+15.3 kJ
Comments
Leave a comment